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53n-3n^2-230=0
a = -3; b = 53; c = -230;
Δ = b2-4ac
Δ = 532-4·(-3)·(-230)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-7}{2*-3}=\frac{-60}{-6} =+10 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+7}{2*-3}=\frac{-46}{-6} =7+2/3 $
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